Solució exercici6-ajax
De wikiserver
La revisió el 15:41, 9 abr 2024 per Mfernandez (Discussió | contribucions)
//fitxer html
<!DOCTYPE html>
<html lang="ca">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Exercici 6 AJAX</title>
</head>
<body>
<h1>Exercici 6 AJAX</h1>
<input type="text" id="input"></input>
<br>Suggeriments:
<div id="contingut"></div>
<script lang="javascript">
var xhr = new XMLHttpRequest();
var contingut = document.getElementById("contingut");
var input = document.getElementById("input");
input.oninput = function () {
xhr.open("GET", "ex6.php?q=" + input.value);
xhr.send(null);
};
xhr.onreadystatechange = function () {
if (xhr.readyState == 4 && xhr.status == 200) {
contingut.innerHTML = xhr.responseText;
}
};
</script>
</body>
</html>//fitxer php
<?php
// Array with names
$a = array("Anna", "Brittany", "Cinderella", "Diana", "Eva", "Fiona", "Gunda", "Hege", "Inga", "Johanna", "Kitty", "Linda", "Nina", "Ophelia", "Petunia", "Amanda", "Raquel", "Cindy", "Doris", "Eve", "Evita", "Sunniva", "Tove", "Unni", "Violet", "Liza", "Elizabeth", "Ellen", "Wenche", "Vicky");
// get the q parameter from URL
$q = $_REQUEST["q"];
$hint = "";
// lookup all hints from array if $q is different from ""
if ($q !== "") {
$q = strtolower($q);
$len = strlen($q);
foreach ($a as $name) {
if (stristr($q, substr($name, 0, $len))) {
if ($hint === "") {
$hint = $name;
} else {
$hint .= "<br>$name";
}
}
}
}
// Output "no suggestion" if no hint was found or output correct values
echo $hint === "" ? "no suggestion" : $hint;
